Optimal. Leaf size=326 \[ -\frac{\sqrt [4]{a} e^3 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} \left (5 \sqrt{a} B-9 A \sqrt{c}\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{6 c^{9/4} \sqrt{e x} \sqrt{a+c x^2}}-\frac{e (e x)^{3/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{3 A e^3 x \sqrt{a+c x^2}}{c^{3/2} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}-\frac{3 \sqrt [4]{a} A e^3 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{c^{7/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{5 B e^2 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2} \]
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Rubi [A] time = 0.338871, antiderivative size = 326, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.292, Rules used = {819, 833, 842, 840, 1198, 220, 1196} \[ -\frac{\sqrt [4]{a} e^3 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} \left (5 \sqrt{a} B-9 A \sqrt{c}\right ) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{6 c^{9/4} \sqrt{e x} \sqrt{a+c x^2}}-\frac{e (e x)^{3/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{3 A e^3 x \sqrt{a+c x^2}}{c^{3/2} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}-\frac{3 \sqrt [4]{a} A e^3 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{c^{7/4} \sqrt{e x} \sqrt{a+c x^2}}+\frac{5 B e^2 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2} \]
Antiderivative was successfully verified.
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Rule 819
Rule 833
Rule 842
Rule 840
Rule 1198
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{(e x)^{5/2} (A+B x)}{\left (a+c x^2\right )^{3/2}} \, dx &=-\frac{e (e x)^{3/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{\int \frac{\sqrt{e x} \left (\frac{3}{2} a A e^2+\frac{5}{2} a B e^2 x\right )}{\sqrt{a+c x^2}} \, dx}{a c}\\ &=-\frac{e (e x)^{3/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 B e^2 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{2 \int \frac{-\frac{5}{4} a^2 B e^3+\frac{9}{4} a A c e^3 x}{\sqrt{e x} \sqrt{a+c x^2}} \, dx}{3 a c^2}\\ &=-\frac{e (e x)^{3/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 B e^2 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{\left (2 \sqrt{x}\right ) \int \frac{-\frac{5}{4} a^2 B e^3+\frac{9}{4} a A c e^3 x}{\sqrt{x} \sqrt{a+c x^2}} \, dx}{3 a c^2 \sqrt{e x}}\\ &=-\frac{e (e x)^{3/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 B e^2 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{\left (4 \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{-\frac{5}{4} a^2 B e^3+\frac{9}{4} a A c e^3 x^2}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{3 a c^2 \sqrt{e x}}\\ &=-\frac{e (e x)^{3/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 B e^2 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}-\frac{\left (\sqrt{a} \left (5 \sqrt{a} B-9 A \sqrt{c}\right ) e^3 \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{3 c^2 \sqrt{e x}}-\frac{\left (3 \sqrt{a} A e^3 \sqrt{x}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{c} x^2}{\sqrt{a}}}{\sqrt{a+c x^4}} \, dx,x,\sqrt{x}\right )}{c^{3/2} \sqrt{e x}}\\ &=-\frac{e (e x)^{3/2} (A+B x)}{c \sqrt{a+c x^2}}+\frac{5 B e^2 \sqrt{e x} \sqrt{a+c x^2}}{3 c^2}+\frac{3 A e^3 x \sqrt{a+c x^2}}{c^{3/2} \sqrt{e x} \left (\sqrt{a}+\sqrt{c} x\right )}-\frac{3 \sqrt [4]{a} A e^3 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{c^{7/4} \sqrt{e x} \sqrt{a+c x^2}}-\frac{\sqrt [4]{a} \left (5 \sqrt{a} B-9 A \sqrt{c}\right ) e^3 \sqrt{x} \left (\sqrt{a}+\sqrt{c} x\right ) \sqrt{\frac{a+c x^2}{\left (\sqrt{a}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{6 c^{9/4} \sqrt{e x} \sqrt{a+c x^2}}\\ \end{align*}
Mathematica [C] time = 0.0657756, size = 120, normalized size = 0.37 \[ \frac{e^2 \sqrt{e x} \left (3 A c x \sqrt{\frac{c x^2}{a}+1} \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{7}{4};-\frac{c x^2}{a}\right )-5 a B \sqrt{\frac{c x^2}{a}+1} \, _2F_1\left (\frac{1}{4},\frac{1}{2};\frac{5}{4};-\frac{c x^2}{a}\right )+5 a B-3 A c x+2 B c x^2\right )}{3 c^2 \sqrt{a+c x^2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.032, size = 308, normalized size = 0.9 \begin{align*} -{\frac{{e}^{2}}{6\,x{c}^{3}}\sqrt{ex} \left ( 9\,A\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ) ac-18\,A\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticE} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ) ac+5\,B\sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-ac}}{\sqrt{-ac}}}}\sqrt{-{\frac{cx}{\sqrt{-ac}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-ac}}{\sqrt{-ac}}}},1/2\,\sqrt{2} \right ) \sqrt{-ac}a-4\,B{c}^{2}{x}^{3}+6\,A{c}^{2}{x}^{2}-10\,aBcx \right ){\frac{1}{\sqrt{c{x}^{2}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )} \left (e x\right )^{\frac{5}{2}}}{{\left (c x^{2} + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B e^{2} x^{3} + A e^{2} x^{2}\right )} \sqrt{c x^{2} + a} \sqrt{e x}}{c^{2} x^{4} + 2 \, a c x^{2} + a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )} \left (e x\right )^{\frac{5}{2}}}{{\left (c x^{2} + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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